7s+14=2s^2+2

Solution for 7s+14=2s^2+2 equation:

7s+14=2s^2+2

We move all terms to the left:

7s+14-(2s^2+2)=0

We get rid of parentheses

-2s^2+7s-2+14=0

We add all the numbers together, and all the variables

-2s^2+7s+12=0

a = -2; b = 7; c = +12;
Δ = b2-4ac
Δ = 72-4·(-2)·12
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{145}}{2*-2}=\frac{-7-\sqrt{145}}{-4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{145}}{2*-2}=\frac{-7+\sqrt{145}}{-4}
$